평균은 넘겠지 (4344)
Created:
이건 출제자가 너무했다..
Bash
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read c
for ((i=0; i<c; i++)); do
read arr
n=${arr::1}
arr=(${arr#* })
sum=0
for g in ${arr[@]}; do
sum=$((sum + g))
done
avg=$((sum*10 / n))
cnt=0
for g in ${arr[@]}; do
if [ $avg -lt $((g * 10)) ]; then
cnt=$((cnt + 1))
fi
done
p=$((cnt*1000000 / n))
e=${p:${#p}-1}
p=${p%$e*}
p=$((5 <= e ? p+1 : p))
n=${p:: -3}
echo $n1.${p#$n}%
done
정답과 똑같이 나오는데 백준에서는 런타임 에러가 든다.
C
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#include <stdio.h>
int main(void) {
int c, n, cnt;
float sum, avg;
scanf("%d", &c);
for (int i=0; i<c; i++) {
scanf("%d", &n);
int arr[n];
for (int j=0; j<n; j++) {
scanf("%d", &arr[j]);
}
sum = 0;
for (int j=0; j<n; j++) {
sum += arr[j];
}
avg = sum / n;
cnt = 0;
for (int j=0; j<n; j++) {
cnt += avg < arr[j] ? 1 : 0;
}
printf("%.3f%%\n", (double)cnt/n*100);
}
return 0;
}
Node.js
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let [c, ...input] = require("fs").readFileSync(0).toString().trim().split("\n");
for (let arr of input) {
[n, ...arr] = arr.split(" ").map(Number);
let avg = arr.reduce((r, x, i) => { return r + x }) / n;
cnt = 0;
for (let g of arr) {
if (avg < g) cnt++
}
p = Math.round(cnt/n*100*1000) / 1000;
console.log(`${p.toFixed(3)}%`);
}
JavaScript의 round()는 소수점 지정이 안되기 때문에 1000을 곱하고 다시 나눈다.
PHP
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<?php
fscanf(STDIN, "%d", $n);
for ($i=0; $i<$n; $i++) {
$arr = explode(" ", trim(fgets(STDIN)));
$m = $arr[0];
$arr = array_slice($arr, 1);
$avg = array_sum($arr)/$m;
$cnt = 0;
foreach ($arr as $x) {
if ($avg < $x) { $cnt++; }
}
echo sprintf("%.3f", ($cnt/$m*100))."%\n";
}
?>
Python3
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c = int(input())
for i in range(c):
arr = list(map(int, input().split()))
n, arr = arr[0], arr[1:]
avg = sum(arr)/n
cnt = 0
for g in arr:
if avg < g: cnt += 1
p = "{:.3f}%".format(cnt/n*100)
print(p)
Ruby
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c = gets.chomp.to_i
for i in 0...c
arr = gets.chomp.split().map {|i| i.to_i}
n, arr = arr[0].to_f, arr.slice(1, arr.size-1)
avg = arr.sum()/n
cnt = 0
for g in arr
cnt += 1 if avg < g
end
p = "%.3f" % (cnt/n*100) + "%"
puts p
end