구구단 (2739)

Baekjoon

Created:

Baekjoon No.2739
간단한 구구단

Bash

Bash
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read n
for i in {1..9}; do
	echo $n \* $i = $((n * i))
done

C

C
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#include <stdio.h>

int main(void) {
	int n;
	scanf("%d", &n);
	for (int i=1; i<=9; i++) {
		printf("%d * %d = %d\n", n, i, n*i);
	}

	return 0;
}

Node.js

JavaScript
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let n = Number(require("fs").readFileSync(0).toString().trim());
for (let i=1; i<=9; i++) {
	console.log(`${n} * ${i} = ${n*i}`);
}

PHP

PHP
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<?php
	fscanf(STDIN, "%d", $n);
	for ($i=1; $i<=9; $i++) {
		echo "$n * $i = ".$n*$i."\n";
	}
?>

Python3

Python
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n = int(input())
for i in range(1, 10):
    print("{} * {} = {}".format(n, i, n*i))

Ruby

Ruby
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n = gets.chomp.to_i
for i in 1..9
  puts "#{n} * #{i} = #{n*i}"
end
#Bash #C #Node.js #PHP #Python3 #Ruby