
간단한 구구단
Bash 
bash
read n
for i in {1..9}; do
	echo $n \* $i = $((n * i))
done1
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C 
c
#include <stdio.h>
int main(void) {
	int n;
	scanf("%d", &n);
	for (int i=1; i<=9; i++) {
		printf("%d * %d = %d\n", n, i, n*i);
	}
	return 0;
}1
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Node.js 
javascript
let n = Number(require("fs").readFileSync(0).toString().trim());
for (let i=1; i<=9; i++) {
	console.log(`${n} * ${i} = ${n*i}`);
}1
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PHP 
php
<?php
	fscanf(STDIN, "%d", $n);
	for ($i=1; $i<=9; $i++) {
		echo "$n * $i = ".$n*$i."\n";
	}
?>1
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Python3 
python
n = int(input())
for i in range(1, 10):
    print("{} * {} = {}".format(n, i, n*i))1
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Ruby 
ruby
n = gets.chomp.to_i
for i in 1..9
  puts "#{n} * #{i} = #{n*i}"
end1
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