AxB (10998)

Created: 2023-01-27 11:57:00

Baekjoon No.10998
간단한 곱셈
이전 문제에서 부호만 바꾸면 된다.

Bash

Bash1
2
read a b
echo $((a * b))

Bash
1 2	read a b echo $((a * b))

C1
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8
#include <stdio.h>

int main(void) {
	int a, b;
	scanf("%d %d", &a, &b);
	printf("%d", a*b);
	return 0;
}

C
1 2 3 4 5 6 7 8	#include <stdio.h> int main(void) { int a, b; scanf("%d %d", &a, &b); printf("%d", a*b); return 0; }

JavaScript1
2
let [a, b] = require("fs").readFileSync(0).toString().trim().split(" ").map(Number);
console.log(a * b);

JavaScript
1 2	let [a, b] = require("fs").readFileSync(0).toString().trim().split(" ").map(Number); console.log(a * b);

PHP1
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<?php
	fscanf(STDIN, "%d %d", $a, $b);
	echo $a * $b;
?>

PHP
1 2 3 4	<?php fscanf(STDIN, "%d %d", $a, $b); echo $a * $b; ?>

Python1
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a, b = map(int, input().split())
print(a*b)

Python
1 2	a, b = map(int, input().split()) print(a*b)

Ruby1
2
a, b = gets.chomp.split().map {|i| i.to_i}
puts a*b

Ruby
1 2	a, b = gets.chomp.split().map {\|i\| i.to_i} puts a*b