입력한 값이 0 0이면 반복문을 빠져나온다.

Bash

while :; do
	read a b
	if [ "$a$b" == "00" ]; then
		break
	fi
	echo $((a + b))
done

while : == while true == 무한루프

C

#include <stdio.h>

int main(void) {
	int a, b;
	while (1) {
		scanf("%d %d", &a, &b);
		if (a == 0 && b == 0) { break; }
		printf("%d\n", a+b);
	}
	return 0;
}

Node.js

let list = require("fs").readFileSync(0).toString().trim().split("\n");
for (let l of list.slice(0,-1)) {
	let [a, b] = l.split(" ").map(Number);
	console.log(a+b);
}

PHP

<?php
	while (1) {
		fscanf(STDIN, "%d %d", $a, $b);
		if ($a == 0 && $b == 0) { break; }
		echo $a + $b."\n";
	}
?>

Python3

while 1:
    a, b = map(int, input().split())
    if a==0 and b==0: break
    print(a+b)

Ruby

while 1
  a, b = gets.chomp.split().map {|i| i.to_i}
  break if a==0 and b==0
  puts a+b
end