A+B - 3 (10950)

Baekjoon

Created:

Baekjoon No.10950
한 번에 출력하지 않아도 된다.

Bash

Bash
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read t
#for i in $(seq $t); do
for ((i=0; i<t; i++)); do
	read a b
	echo $((a + b))
done

seq 명령어도 먹히지 않는다…

C

C
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#include <stdio.h>

int main(void) {
	int t, a, b;
	scanf("%d", &t);
	for (int i=0; i<t; i++) {
		scanf("%d %d", &a, &b);
		printf("%d\n", a+b);
	}
	return 0;
}

Node.js

JavaScript
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let [t, ...list] = require("fs").readFileSync(0).toString().trim().split("\n");
for (let i of list) {
	let [a, b] = i.split(" ").map(Number);
	console.log(a + b);
}

PHP

PHP
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<?php
	fscanf(STDIN, "%d", $n);
	for ($i=0; $i<$n; $i++) {
		fscanf(STDIN, "%d %d", $a, $b);
		echo $a + $b."\n";
	}
?>

Python3

Python
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t = int(input())
for i in range(t):
    a, b = map(int, input().split())
    print(a+b)

Ruby

Ruby
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t = gets.chomp.to_i
for i in 0...t
  a, b = gets.chomp.split(" ").map {|i| i.to_i}
  puts a+b
end
#Bash #C #Node.js #PHP #Python3 #Ruby