나머지 (10430)

Created:

Baekjoon No.10430
그냥 입력값 받고 주어진 대로 연산만 하면 되는 문제.

Bash

Bash
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read a b c
echo $(((a + b) % c))
echo $((((a % c) + (b % c)) % c))
echo $(((a * b) % c))
echo $((((a % c) * (b % c)) % c))

C

C
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#include <stdio.h>

int main(void) {
	int a, b, c;
	scanf("%d %d %d", &a, &b, &c);
	printf("%d\n", (a+b)%c);
	printf("%d\n", ((a%c)+(b%c))%c);
	printf("%d\n", (a*b)%c);
	printf("%d\n", ((a%c)*(b%c))%c);
	return 0;
}

Node.js

JavaScript
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let [a, b, c] = require("fs").readFileSync(0).toString().trim().split(" ").map(Number);
console.log((a+b)%c);
console.log(((a%c)+(b%c))%c);
console.log((a*b)%c);
console.log(((a%c)*(b%c))%c);

PHP

PHP
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<?php
	fscanf(STDIN, "%d %d %d", $a, $b, $c);
	echo ($a+$b)%$c."\n";
	echo (($a%$c) + ($b%$c))%$c."\n";
	echo ($a*$b)%$c."\n";
	echo (($a%$c) * ($b%$c))%$c."\n";
?>

Python3

Python
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a, b, c = map(int, input().split())
print( (a+b)%c )
print( ((a%c)+(b%c))%c )
print( (a*b)%c )
print( ((a%c)*(b%c))%c )

Ruby

Ruby
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a, b, c = gets.chomp.split().map {|i| i.to_i}
puts (a+b)%c
puts ((a%c) + (b%c))
puts (a*b)%c
puts ((a%c) * (b%c))